Question

A body moves with an initial velocity of 2m/s and uniform acceleration of 3m/s². Calculate the velocity when it has travelled a distance of 77 m​

Answer 1

Explanation:

The initial velocity = 2 m/sec

Uniform Acceleration = 3 m/sec²

Distance covered = 77m

From the equations of motion :-

We know that :-

2as = v²-u²

V² = 2as + u²

V² = 2*3*77+(2)²

V²=462+4=466

v = \sqrt{466}v=

466

So,

Final velocity = root466 m/sec

Hope this will be helping you...

Answer 2

here is your answer

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