Question

a body moves with an initial velocity of 5m/s and uniform acceleration of 0.4 m/s . calculate the velocity after 12sec and distance travelled in this time

Answer 1

You can use the formula:

s=ut+1/2at^2

where s=distance travelled

u=initial velocity

a=acceleration

t=time

ATQ, u=0m/s(as the body starts from rest, thus it's obvious that the initial velocity will be 0),t=20s, a=5m/s^2, s=?

Now put the value in the formula:

s=ut+1/2at^2

s=0(20s)+ 1/2(5m/s^2)(20s)^2

s=0+1/2(5m/s^2)(400s^2)

s=1/2(2000m)

s=1000m

Thus, distance travelled is 1000m