Question

a body moves with and internal velocity of 5 metre per second and uniform acceleration of 0.4 metre per second square calculate the velocity after the 12second and distance travelled during this time​

Answer 1

final velocity = v= u + at

v = 5+ 0.4*12

v= 4.8 m/s

distance covered in 12 sec =

x= ut + 0.5* at^2

x= 5*12 + 0.5* 0.4*144

x= 60 + 28.8

x= 88.8 m