Question

A BODY MOVES WITH INITIAL VELOCITY 10 M S -1 AND ACCELERATES AT 4 M S -2 FIND ITS VELOCITY AFTER 10 S​

Answer 1

Given:

• Initial velocity (u) = 10m/s

• Acceleration (a) = $\sf { 4 \: m/{s}^{2} }$

• Time (t) = 10 s

To calculate:

• Its velocity after 10s i.e its final velocity.

Calculation:

By using the first equation of motion :

• v = u + at

Where,

• v = final velocity

• u = initial velocity

• a = acceleration

• t = time taken

Calculating its final velocity by substituting the values, we get :

→ v = 10 + ( 4 × 10 ) m/s

→ v = 10 + 40 m/s

→ $\boxed{\sf \red {v = 50 \: m/s }}$

Therefore, its velocity after 10 seconds is 50 m/s.

More information:

Equations of motion:

• v = u + at
• s = ut + ½at²
• 2as = v² - u²

Where,

• v = final velocity

SI unit = m/s

• u = inital velocity

SI unit = m/s

• a= acceleration

SI unit = m/s²

• t = time

SI unit = seconds (s)

• s = distance/displacement

SI unit = metre (m)

Also,

• When body starts from rest, its initial velocity (u) is 0.
• When body comes to rest or applies brake, its final velocity (v) is 0.
• Negative acceleration is called retardation.

Answer 2

By using the first equation of motion :

$\fbox \green{v=u+at}$

Where,

◑ v = final velocity

◑ u = initial velocity

◑ a = acceleration

◑ t = time taken

✯Calculating its final velocity by substituting the values, we get :

⇛ v = 10 + ( 4 × 10 ) m/s

⇛ v = 10 + 40 m/s

⇛ $\fbox \orange{v=50m \: per \:sec}$

Therefore, its velocity after 10 seconds is 50 m/s.

More information:

Equations of motion:

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ↝v=u + at \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ↝ ↝s=ut + ½at² \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:↝↝↝2as = v² - u²$

$\fbox \pink{ハンはジャクソンが大好き}$