Question

A body moves with uniform velocity of u = 7 m/s
from t = 0 to 1 = 1.5 sec. For > 1.5 s, it starts moving
with an acceleration of 10 m/s2. The distance trav-
elled between 1 = 0 to 1 = 3 sec will be
(A) 47.75 m
(B) 32.25 m
(C) 16.75 m
(D) 27.50 m
​

Answer 1

Answer:

Distance covered in first 1.5 sec =ut=1.5×7=10.5m

Distance covered in last 1.5 sec =ut+

2

1

×10×t

2

=1.5×7+5×2.25=10.5+11.25=21.75m

Total distance =10.5+21.75=32.25m