Question

A body movespecially with an initial velocity of 2m/s.and uniform acceleration 3m/s^2.calculate the velocity when it has travelled a distance 77metres

Answer 1

Answer:

21.58 m/s

Explanation:

Given: Initial velocity(u)= 2m/s

Acceleration(a)= 3m/s^2

Distance(s)=77 m

Final velocity(v)=?

By Newton's third law of motion,

v^2-u^2=2as

v^2-(2)^2=2(3)(77)

v^2-4=462

v^2=462+4

v^2=466

v=21.5

Final Velocity= 21.58m/s