a body movies uniform acceleration crossing the distance of 15 m in 3rd second and 23 m in 5 th second the distance in 10 second will be
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initial velocity=s1/t1=15/3=5m/s
final velocity=s2/t2=23/5=4.6m/s
time difference=5-3=2s
acceleration=v-u/t
=4.6-5/2==-0.2m/s²
velocity in 10s=a*t=-0.2*10=-2m/s
distance covered in 10s=ut+1/2at²
Here u=0
=1/2*-0.2*100=-10m
final velocity=s2/t2=23/5=4.6m/s
time difference=5-3=2s
acceleration=v-u/t
=4.6-5/2==-0.2m/s²
velocity in 10s=a*t=-0.2*10=-2m/s
distance covered in 10s=ut+1/2at²
Here u=0
=1/2*-0.2*100=-10m
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