Physics, asked by sujajiju, 7 hours ago

A body moving along a straight line at 100 m/s undergoes an acceleration of - 2m/s2
.
What is the distance travelled if the final velocity is 40 m/s?
pls help me with this question

Answers

Answered by ribhutripathi18116
0

V=U+at

40=100-2t

2t=60

t=30 seconds

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Answered by dejavuXOXO
0

Answer:

Distance travelled is 2100 m.  

Explanation:

Initial Velocity (u) = 100 m/s

Final Velocity (v) = 40 m/s

Acceleration (a) = -2 m/s²

Distance travelled = ??

Using Equations of Motion,

⇒ v² = u² + 2as

⇒ (40)² = (100)² + 2(-2)(s)

⇒ 1600 = 10000 + (-4s)

⇒ 4s = 10000 - 1600

⇒ s = 8400/4

⇒ s = 2100 meters

Distance travelled is 2100 m.  

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