A body moving along a straight line at 100 m/s undergoes an acceleration of - 2m/s2
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What is the distance travelled if the final velocity is 40 m/s?
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V=U+at
40=100-2t
2t=60
t=30 seconds
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Answered by
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Answer:
Distance travelled is 2100 m.
Explanation:
Initial Velocity (u) = 100 m/s
Final Velocity (v) = 40 m/s
Acceleration (a) = -2 m/s²
Distance travelled = ??
Using Equations of Motion,
⇒ v² = u² + 2as
⇒ (40)² = (100)² + 2(-2)(s)
⇒ 1600 = 10000 + (-4s)
⇒ 4s = 10000 - 1600
⇒ s = 8400/4
⇒ s = 2100 meters
Distance travelled is 2100 m.
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