Question

. A body moving along a straight line at 20m/s undergoes an acceleration of 4m/s2. After two seconds what will be its speed. Also find the displacement.

Answer 1

v = u + a*t
speed = 20 + 4*2 = 28 m/s
s = u*t + 0.5*a*t^2
displacement = 20*2 + 0.5*4*4 = 48 m

Answer 2

Hello!

A body moving along a straight line at 20 m/s undergoes an acceleration of 4m/s². After two seconds what will be its speed. Also find the displacement.

* What will be its speed, we have the following data:

Vi (initial velocity) = 20 m/s

Vf (final velocity) = ? (in m/s)

t (time) = 2 s

a (acceleration) = 4 m/s²

We apply the data to the formula of the hourly function of the velocity, let us see:

$V_f = V_i + a*t$

$V_f = 20 + 4*2$

$V_f = 20 + 8$

$\boxed{\boxed{V_f = 28\:m/s}}\Longrightarrow(final\:velocity)\:\:\:\:\:\:\bf\green{\checkmark}$

* Find displacement, we have the following data:

Vi (initial velocity) = 20 m/s

t (time) = 2 s

a (acceleration) = 4 m/s²

d (displacement) = ? (in m)

By the formula of the space of the Uniformly Varied Movement, it is:

$d = v_i * t + \dfrac{a*t^{2}}{2}$

$d = 20 * 2 + \dfrac{4*(2)^{2}}{2}$

$d = 40 + \dfrac{4*4}{2}$

$d = 40 + \dfrac{16}{2}$

$d = 40 + 8$

$\boxed{\boxed{d = 48\:m}}\longleftarrow(displacement)\:\:\:\:\:\:\bf\green{\checkmark}$

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