Question

A body moving along a straight line at 20m/s undergoes an
acceleration of -4m/s2
.

The velocity of the object after 2 seconds will be:

Answer 1

Answer:

Data:

u=20 m/s

t=2 s

a=-4m/s/s {The unit given in the question is not correct}

v=?

Solution:

v = u + at = 20 + (-4)2 =20 - 8 = 12 m/s in tne initial direction of motion.

Explanation:

PLZ ADD MY ANSWER AS BRAINLIEST

Answer 2

$\underline{ \underline{\large \sf{Corrected \: question:-}}}$

• A body moving along a straight line at 20m/s undergoes an acceleration of -4m/s² .The velocity of the object after 2 seconds will be?

$\underline{ \underline{\large \sf{Information \: given \: to \: us:-}}}$

• A body is moving at along a straight line at 20 m/s
• Acceleration of the body is -4m/s²

$\underline{ \underline{\large \sf{Need \: to \: be \: calculated \: us:-}}}$

• Velocity of body after 2s

$\underline{ \underline{\large \sf{Performing \: Calculations:-}}}$

Here we have been provided with the values of acceleration and the speed at which body had been moving.

So,

• Initial velocity is 20 m/s
• Time taken is 2 s

We would be using the formula of, First equation of motion.

• v = u + at

Here v is the velocity of that body.

Evaluating the required values,

➛ v = 20 + (-4m/s) × 2

Multiplying -4 with 2

➛ v = 20 + (-8m/s)

Opening bracket of -8ms

➛ v = 20 - 8m/s

Now, on subtracting 20 with 8

➛ v = 12 m/s

$\underline{ \underline{\large \sf{Conclusion:-}}}$

• Velocity of the object after 2 seconds will be 12 m/s