Question

A body moving along a straight line is given a uniform accelaretion . It state from rest and covers displacement S1 S2 S3 in equal time interval so find the ratio of S1:S2:S3

Answer 1

Answer:

A body starting from rest

with constant acceleration. what of distance covered by the body the 5th seconds to that covered in 5 second

Answer 2

Explanation:

The dist. travelled is equal in all intervals .Let that be s.

Now, Average velocity=(v1+v2+v3)/3

=(s/t1+s/t2+s/t3)/3

=s(1/t1+1/t2+1/t3)/3 ….(1)

Also, Average velocity=Total dist./total time

=s/(t1+t2+t3) ...(2)

From (1)&(2)

s/(1/t1+1/t2+1/t3)/3=s/(t1+t2+t3)

s will cancel out s, and shifting 3 on right hand side we get;

1/t1+1/t2+1/t3=3(t1+t2+t3)

Hence prooved.

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