Question

a body moving along a straight line with constant acceleration covers 50m in first five seconds and 100 m in next 5 seconds. Find the initial velocity and acceleration of the body​

Answer 1

Distance in 2sec=14m

S=U(2)+

2

1

a(2)

2

14=24+29→4+9=7 ....(1)

(88+14)=64+

2

1

a(36)

102=64+189

4+3a=17 ....(2)

2a=10⟹

4=2m/s

9=5m/s

Distance in 5 sec.

S

1

=2(5)+

2

1

(5)(25)

=10+62.5=72.5m

Distance in 4 sec

S

2

=2(4)+

2

1

(5)(16)

=8+40=48m

Distance in 5

th

sec=72.5−48

=24.5m