A body moving along a straight line with uniform acceleration crosses points A and B with velocities u and v. The velocity, with which the body crosses a
point C, at one-third distance from A is
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Explanation:
A body travelling with uniform acceleration crosses two point A and B with velocities 20 m s^-1 and 30 m s^-1 respectively. The speed of the body at the mid-point of A and B is. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams. =√400+2×125x×x=√650=25.5m/s.
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