Question

A body moving along a straight path at velocity of 20 m/s attains an acceleration of 4 m/s^2. Calculate the velocity of the body after 2 seconds.

Answer 1

Explanation:

Initial velocity  u=5 m/s

Final velocity  v=25 m/s

Time  t=5 s

Using   v=u+at

Or   25=5+a×5

⟹ a=4 m/s2

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Answer 2

Given,

(u) Initial velocity = 20 m/s

(v) Final velocity = x

(a) Acceleration = 4 m/s^2

(t) Time = 2 secs

Using the first equation of motion,

v = u + at

x = 20 m/s + (4 * 2)

x = 20 + 8 m/s

x = 28 m/s

Therefore, The final velocity attained by the body is 28 m/s

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