Question

A body moving at 12 m/s is uniformly accelerated. After traveling a distance of 100 m, it has a velocity of 20 m/s. Find the time taken to travel a distance of 100 m and the acceleration.

Answer 1

Answer:

speed =distance /time

12=100/time

100/12=time

solve this u get time

put t value in this equation

100=20t+1/2at²

Answer 2

Explanation:

Initial Velocity u = 12m/s

distance s = 100 m

Final velocity v = 20m/s

By the Equation v^2 - u^2 = 2as

we can find Acceleration a

(20)^2 - (12)^2 = 2×a×100

400 - 144 = 200a

256 = 200a

a = 256/200 = 1.28 m/s^2

Now To find out Time , We can use equation v = u + at or the equation s = ut + 1/2at^2

Here we use v = u + at

20 = 12 + 1.28t

8 = 1.28t

t = 8/1.28 = 6.25 second