Question

A body moving at 2 m/s can be stopped over a distance x. If its kinetic energy is tripled, how long will it go before come to rest, if the retarding force remains unchanged?

Answer 1

Answer:

To double the K.E , the new velocity =2

2

ms

−1

let the retardation be =a

we know v

2

=2×a×x

initial v=2

so 2

2

=2×a×x (1)

when v=2

2

ms

−1

so(2

2

)

2

=2ax

1

−(2)

From (1) and (2), x

1

=2x

Answer 2

Answer:

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