Question

A body moving from rest travel for 90 second with an acceleration of 2 metre per second square the distance covered by the body is​

Answer 1

Answer:

apply sum of distance

Explanation:

aage tio tum samajhdar ho

Answer 2

Answer :

Initial velocity $=$ zero

Time of journey = 90s

Acceleration = 2m/s²

We have to find distance covered by body in the given interval of time$.$

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◈ Since, acceleration of body is said to be constant throughout the motion, we can apply equation of kinenatics to solve this question.

2nd eq. of kinematics is given by

• s = ut + 1/2(at²)

s denotes distance

u denotes initial velocity

t denotes time

a denotes acceleration

⇒ s = ut + 1/2(at²)

⇒ s = (0×90) + 1/2(2×90²)

⇒ s = 0 + 1/2(2×8100)

⇒ s = 8100m = 8.1km