Question

A body moving in a circular path of radius R completes
one round in 10 s. The ratio of the magnitude of
displacement to the distance travelled in 2.5 s is
tt = 22/7)
1) 772:22
2) 14:1172
3) 11/2:14
4) 7:11​

Answer 1

Answer:

distance travelled in 2.5s=perimeter/4=pi×R/2

dispalcement=(2)^1/2R

so required ratio=1.414×7×2/22=19.7/22(approx) will be the answer.

hope it helps

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