Question

A body, moving in a straight line, with an initial
velocity u and a constant
acceleration a, covers a
distance of 40 m in the 4th second and a distance
of 60 m in the 6th second. The values of u and a
respectively are​

Answer 1

Answer:

u = 10 m/s    a = 0 m/$s^{2}$  

Explanation is given in the attachment.

Explanation:

51c7f26e79d32db8c2dddc417d047606.pdf

Answer 2

Answer:

Snth=u+g/2 (2n-1)

su=u+g/2 (2(4)-1)

40=u+g/2 (7) (i)

S6 = u+g/2 (2(6)-1)

60=u+g/2 (ii)

from eg i nd ii we get g =10ms,u=5ms