Question

a body moving in intial velocity of 5 meters per second has a constant acceleration of 7 meters per second find the distance traveled by the body in the fourth second​

Answer 1

Given: u=5m/s a=7m/s^2 t= 4s

$s = ut + \frac{1}{2} a {t}^{2}$

$= 5 \times 4 + \frac{1}{2} \times 7 \times {4}^{2}$

$= 20 + 56$

$= 76m$

Answer 2

u=5m/s

a=7m/s sq

s=?

t=4sec

s=ut+1/2at sq

s=5×4+1/27×4×4

s=20+7×8

s= 76