Question

A body moving on a ground with a velocity of 15m/s comes to rest after
covering a distance of 25m. If ‘g’ = 10 ms -2 ,find the coefficient of friction between
the ground and the body.

Answer 1

Answer:

0.45

Explanation:

g is negative as it is acting downward direction

Answer 2

Answer :The coefficient of friction between  the bottom  and the body is  0.45

Explanation:

Coefficient of friction,: Ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together.

μ = F/N=ma/mg= a/g

Applying laws of motion

v² = u²+2as

According to the given conditions

we have v=0m/s ; u=15m/s ; s=25m

0² = (15)² +2a(25)

-225= 50a

a=-225/50

a=4.5m/s²

The coefficient of friction is given as

μ= ma/mg

=a/g

=4.5/10

μ=0.45

The coefficient of friction between

the ground and the body is  0.45

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