Question

A body moving with 10 M per second comes to rest in 2 second find retardation

Answer 1

it -10/2
=-5m/sec sq.
HOPE THIS WOULD HELP

Answer 2

Hi Friend
v=10m/s
u=0
t=2sec
So,
v = u + at
10 = 0 + a×2
10 = 2a
a =
$\frac{10}{2}$
$a = 5mper {sec}^{2}$
So retardation produced is 5m/sec^2

Hope it helps you ☺

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