Question

A body moving with 20m/s accelerates to 25m/s in 3 sec. Find acceleration and
distance travel in 3 sec.(for solve answer the pattern of class 9th)​

Answer 1

Answer:

u= 20m/s

v=25m/s

a =v-u/t

a=25-20/3

a=5/3

a=1.667m/s^2

Answer 2

Answer:

u=20m/s

v=25m/s

t=3s

therefore,a=(v-u)/t

=(25-20)/3 m/s^2

=5/3 m/s^2

=1.67 m/s^2

now,s=ut+1/2(at^2)

=(20×3)+1/2(5/3×3×3)

=5×3(4+1/2)

=15(9/2)

=135/2

=67.5 m