Question

A body moving with 20m/s turns by 60degree and continues with 20m/s Find change in velocity

Answer 1

Answer:

it may 3..........ok...

Answer 2

Answer:

The body is moving with the same velocity 20m/s.

Explanation:

Given a body is moving with a velocity, $\vec u = 20m/s$

Then, it turns by 60° and continues with the same velocity, $\vec v = 20m/s$

The difference in the velocity is given $\Delta v=\vec v -\vec u$

which may also be written as $\Delta v=\vec v+(-\vec u)$

which says that vector $\vec u$ has reversed the direction.

Then the angle between the two vectors is equal to 120°, as shown in the second figure.

Thus, the magnitude of the resultant vector is given by  

$|\Delta v|=|\vec v+(-\vec u)|$

       $=\sqrt{(20)^{2}+ (20)^{2}+2\times20\times20cos120}$

      $=\sqrt{(20)^{2}+ (20)^{2}+2\times20\times20\times\dfrac{-1}{2} }$

      $=\sqrt{(20)^{2}+ (20)^{2}-20\times20 }$

      $=\sqrt{(20)^{2} } =20m/s$

Therefore, there is no change in the magnitude of the velocity, the body is moving with the same velocity 20m/s.

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