A body moving with a constant acceleration travels the distance 3m and 8m respectively in 1s and 2s.Calculate the initial velocity and acceleration of the body
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Using, s=ut+ 1/2 at²
S1 = u + 1/2a
or, 3 = u + a/2
∴a = 6 - 2u
S2 = 2u + 1/2a × 4
8 = 2u + 2a
Solving the equations,
8 = 2u+2(6−2u)
8 = 2u+12−4u
2u = 4
u = 2m/s
∴a = 6−2u
= 6−4
= 2ms^-2
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