Question

A body moving with a speed 10 metre per second due to north takes a left turn through 60 degrees and continues at the same speed. The change in its velocity is ​

Answer 1

Answer:

The change in its velocity is ​ 10 m/s

Explanation:

A body moving with a speed 10 meter per second due to north takes a left turn through 60 degrees and continues at the same speed. The change in its velocity is ​

Considering East as i  & North as j

Velocity of body = 10Cos90° i  + 10Sin90°j

= 0 + 10j

Now turn left at 60° means toward west

Velocity = 10Cos(90 +60)i  + 10Sin(90 + 60)j

= 10(-√3/2)i + 5j

= -5√3i + 5j

Change in velocity = (-5√3i + 5j) - (0 + 10j)

= -5√3i - 5j

√(-5√3)² + (-5)² = √100 = 10 m/s

The change in its velocity is ​ 10 m/s

Answer 2

Answer:

For change in n velocity use farmula

Explanation: Answer attached. ,10 m/s