Question

A body moving with a speed of 30 km/h is
brough in Rech in 10 s Wlhat is the negative
acceleration and the distance travelled
by the body before coming to
riest​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 30 km/h = 8.33 m/s

Final velocity, v = 0

Time taken, t = 10 seconds

To Find,

Acceleration, a = ?

Distance covered, s = ?

According to the 1st equation of motion,

We know that

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ 0 = 8.33 + a × 10

⇒ - 8.33 = 10a

⇒ - 8.33/10 = a

⇒ a = - 0.833 m/s².

Hence, the acceleration of body is - 0.833 m/s².

Now, the distance covered, s,

According to the 3rd equation of motion,

We know that

v² - u² = 2as

So, putting all the values again, we get

⇒ v² - u² = 2as

⇒ (0)² - (8.33) = 2 × (- 0.833) × s

⇒ 69.3889 = - 1.666s

⇒ 69.3889/1.666 = s

⇒ s = 41.65 m

Hence, the distance covered by object is 41.65 m.

Answer 2

Given:

A body moving with a speed of 30 km/h is

brough in Rech in 10 s

To find:

What is the negative acceleration and the distance travelled by the body before coming to riest

STEP BY STEP EXPLANATION:

CASE 1:

Formula will be used

v = u + at

SO,

➭ v = u + at

➭ 0 = 8.33 + a × 10

➭ 8.33 = 10 a

➭ $\frac{8.33}{10} = a$

➭ a = 0.833

∴ thus the acceralation of body = 0.833

CASE 2:

formula used

SO,

➭${v}^{2} - {u}^{2} = 2as \\ (0 {)}^{2} - (8.33) = 2 \times ( - 0.833) \times s$

➭ 69.3889 = - 1.666s

➭$\frac{69.3889}{1.666 } = s$

➭ s = 41.65m

∴ Thus,the distance covered by object = 41.65 m

Hence verified !