Question

a body moving with a speedmof 10m /sec is accelerated at rate of 2m /sec . calculate diatance covered in 5 sec​

Answer 1

Explanation:

Hope you understand that problem

Answer 2

SoluTion :

✴ Given :-

• Initial speed of body = 10m/s
• Acceleration = 2m/s$^2$
• Time interval = 5sec

✴ To Find :-

• Distance covered by body in the given time interval

✴ Formula :-

✒ As per third equation of kinematics, Formula of distance covered by body in constant acceleratory motion is given by...

$\boxed{\sf{\pink{\large{s=ut+\dfrac{1}{2}at^2}}}}$

✴ Calculation :-

$\rightarrow\sf\:s=(10\times 5)+[\dfrac{1}{2}\times 2\times (5)^2]\\ \\ \rightarrow\sf\:s = 50+25\\ \\ \rightarrow\:\boxed{\sf{\purple{\large{s=75\:m}}}}$

▪ Acceleration is a vector quantity.

▪ Vector quantity has both magnitude as well as direction.

▪ Acceleration can be positive, negative and zero.

▪ Negative sign of acceleration shows retardation.