Question

A body moving with a uniform acceleration had velocities of 20m/s and 30m/s when passing the points P and Q of its path .Find the velocity midway between P and Q (in m/s)

Answer 1

Explanation:

The velocity midway between P and Q is:

(20+30)/2= 50/2

= 25m/s.

Answer 2

Answer:

$\sqrt{650\\}$

Explanation:

Let acceleration be a, and the distance between P and Q be s.

So,  using equation of motion

$V^{2}$ = $u^{2}$ + 2as

Solving, we get: as = 250.

Now, when calculating the velocity at the point midway, we'll take the distance to be d/2, with the same acceleration, and initial velocity 20 m/s (or final 30 m/s, but that one was simpler).

Applying the equation of motion:

Using as= 250:

And, v =  m/s, which is a scary number.

Properly, v = 25.495 m/s.