A body moving with a uniform velocity of 10 ms power-1' comes to rest with anacceleration
of 2ms power-1 Calculate the distance travelled by it before itcomes to rest from a velocity
of 10 ms power-1
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Answer:
Given,
u=10m/s
a=2m/s
2
t=4sec
Acceleration, a=
t
v−u
2=
4
v−10
v=10+8=18m/s
The correct option is D.
please mark as brilliant answer
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