Question

A body moving with a velocity 10 m/s comes to rest in 5 seconds. What is the retardation?​​

Answer 1

Given :

• Initial velocity of the body = 10m/s

• Time taken by the body to come to rest = 5 seconds

To Find :

• The retardation produced in the body

Solution :

Using first equation of motion, v = u + at

Here,

• v is final velocity of the body

• u is initial velocity of the body

• a is acceleration of body

• t is time

We have,

• v = 0 {since it comes to rest}

• u = 10 m/s

• t = 5 sec

Substituting the values,

➙ 0 = 10 + a(5)

➙ 0 = 10 + 5a

➙ - 10 = 5a

➙ a = -10/5

➙ a = -2 m/s²

Hence, the retardation produced in the body is 2m/s².

Answer 2

Answer:

Answer is 5m/s^2

Explanation:

u=10m/s

v=0

t=2sec

a=?

We can use the first equation of motion

v=u+at

a=(v-u)/t

a= -10/2

a= -5m/s^2

So retardation is 5m/s^2