A body moving with a velocity of 2 ms-¹ across a velocity of 10 ms-¹ 5 sec find it acceleration
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Answered by
1
Answer:
a= (v-u)/t
a= (10-2)/5
a= 8/5msec^-2
this is the correct answer
Answered by
1
Answer:-
- Initial velocity=u=2m/s
- Final velocuty=v=10m/s
- Time=t=5s
☆Acceleration=v-u/t
➡Acceleration=10-2/5
➡Acceleration=8/5
➡Acceleration=0.4m/s²
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