Physics, asked by vrushankaadepu4511, 11 months ago

A body moving with a velocity of 40m/s is brought to rest in 5seconds,what is it acceleration

Answers

Answered by DRJEASWARY
0

Answer:

given that,

velocity :- 40m/s

time:- 5seconds

acceleration=velocity/time

=40m/s/5s

=8m/s2

the acceleration of the body is 8m/s2

Answered by harisreeps
0

Answer:

A body moving with a velocity of 40m/s is brought to rest in 5seconds, its acceleration is 8m/s^{2}

Explanation:

  • We know the equation of motion

       V=u+at

where,

V- the final velocity

u- the initial velocity

a- acceleration of the body

t- time to change the velocity

S- distance moved

  • The acceleration is the change in velocity divided by time

using the first equation of motion acceleration of the body is

a=\frac{V-u}{t}

from the question, we have

the initial velocity u=40m/s

the body brought to rest so

the final velocity V= 0

the time taken t=5s

therefore the acceleration a=\frac{0-40}{5} =-40/5=-8m/s^{2}

the negative sign is due to retardation

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