Question

A body moving with a velocity of 50cm/sec undergoes a uniform acceleration of 20cm/sec². What is its velocity after 4 sec ? (I need the answer ASAP !! Plzz)

Answer 1

$\boxed{\rm{\blue{Find \longrightarrow }}}$

Velocity After 4 sec

$\boxed{\rm{\orange{Given \longrightarrow }}}$

Initial velocity [v]= 50cm/sec= 0.5 m/s

Acceleration [a]= 20cm/sec= 0.2 m/s

Time Taken [t] = 4 sec

$\boxed{\rm{\pink{Formula \ used \longrightarrow }}}$

$\sf{ a= \dfrac{v-u}{t}}$

where a= acceleration

u= initial velocity

v= final velocity

t= time taken

$\boxed{\rm{\red{SoLution \longrightarrow }}}$

put value in the formula we get,

$\sf{0.2 = \dfrac{v-0.5}{4}}$

$\sf{ 0.2\times 4 = v - 0.5}$

$\sf{v=0.8 - 0.5= 0.3m/s}$

$\underline{\bf{\therefore Velocity\ after\ 4 sec = 0.3m/s}}$

__________________________

Answer 2

Answer:

here is your answer ❥

To find:

velocity after 4 sec.

Given:

u[ initial velocity]= 50cm/sec= 0.5m/sec.

a[ acceleration] = 20cm/sec²= 0.2m/sec²

t[ time]= 4sec.

v [ final velocity]= ?

we know that, a= v-u/t

at= v-u

v= u+at

=( 0.5+ 0.2×4)m/s

=( 0.5+ 0.8 )m/s

= 1.3 m/s

So, the velocity after 4 sec is 1.3 m/s

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