Question

A body moving with an initial velocity of 36 kilometre per hour accelerates uniformly at the rate of 4 metre per second square for 15 seconds calculate the total distance travelled and the final velocity

Answer 1

Answer:

distance,s=600m

final velocity,v=70m/s

Explanation:

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given,

u=36km/hr=36×(5/18)m/s=10m/s

t=15s

a=4m/s^2

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we can use the equations of motion here because the body moves with uniform acceleration.

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$s = ut + \frac{1}{2} a {t}^{2} \\ = 10 \times 15 + \frac{1}{2} \times 4 \times {15}^{2} \\ = 150 + 225 \times 2 \\ = 600m$

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by substituting the value of 's' in the next equation,we will get the final velocity,

${v}^{2} = {u}^{2} + 2as \\ {v}^{2} = {10}^{2} + 2 \times 4 \times 600 \\ {v}^{2} = 100 + 2 \times 4 \times 600 \\ {v}^{2} = 4900 \\ v = \sqrt{4900} \\ v = 70$

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hope it helps...!!!