Question

A body moving with an initial velocity of 36km/h accelerates uniformly at the rate of 4m/s^2 for 15 seconds. Calculate the total distance travelled in 20s and the final velocity.​

Answer 1

Answer

we know that s=ut+1\2at*2

so

s=150 + 1\2 * 4*225

s for 15 sec will be 600m

in 2nd situation v will be constant so by solving further

we will get answer

Explanation:

Answer 2

Answer:

Total distance = 950 m

Explanation:

u = 36 m/s = 10m/s

a = 4 m/s^2

t = 15 s

• v = u+at

= 10+4×15

= 70 m/s

Total distance = distance in 15s + distance in 5s

= (ut+1/2at^2)+(vt)

= (10×15+1/2×4×15×15) + (70×5)

= 150+450+350

= 950m