Question

A body moving with an initial velocity of 40m/s is brought to rest in a distance of 80m. assuming the deccalaration to be uniform. calculate the relation and time interval

Answer 1

Initial velocity (u) = 40 m/s

Final velocity (v) = 0 m/s

Distance traveled (s) = 80 m

Let the acceleration be a.

Let the time taken be t.

Now, using third equation of motion:

$v^2 = u^2 + 2as$

$0^2 = 40^2 + 2 \times a \times 80$

$a = -\frac{40 \times 40}{160}$

a = - 10 $\(\frac{m}{s^2}\)$

$v = u + at$

$t = \frac{0 -40}{-10}$

t = 4 seconds