Physics, asked by Rakshitsrivastava, 6 hours ago

A body moving with an initial velocity of 5 m/s accelerates at 2 m/s?. Its velocity after 10 s is (a)20 m/s (b)25 m/s (c) 5 m/s (d) 22.5 m/s​

Answers

Answered by kritishpanda1
5

Explanation:

v=u+at

v=5+(2×10)

v=5+20

v=25 m/s

option (b)

Answered by Anonymous
44

Answer:

Gɪᴠᴇɴ :

  • ➛ Initial velocity = 5 m/s.
  • ➛ Acceleration = 2 m/s².

\begin{gathered}\end{gathered}

Tᴏ Fɪɴᴅ :

  • ➛ Velocity after 10 seconds.

\begin{gathered}\end{gathered}

Cɴ :

↝ Here the concept of 1st equation of motion has been used. Here we are given that the initial velocity of the body is 5m/s. The time taken is 10 sec and the acceleration is 2m/s². Now, as per the situation we need to apply the first equation of motion.

\begin{gathered}\end{gathered}

Usɪɴɢ Fᴏʀᴍᴜʟᴀ :

\star First equation of motion :

{\longrightarrow{\underline{\boxed{\pmb{\sf{v = u  +  at}}}}}}

Where, 

  • ↠ v = final velocity
  • ↠ u = initial velocity
  • ↠ a = acceleration 
  • ↠ t = time taken.

\begin{gathered}\end{gathered}

Sᴏʟᴜᴛɪᴏɴ :

☼ Finding the final velocity by substituting the values in the formula :-

{\longrightarrow{\sf{v = u  + at}}}

{\longrightarrow{\sf{v = 5  + (2 \times 10)}}}

{\longrightarrow{\sf{v = 5  + (20)}}}

{\longrightarrow{\sf{v = 5  + 20}}}

{\longrightarrow{\sf{v = 25 \: m/s}}}

\bigstar \: {\underline{\boxed{\sf{Final \:  velocity = 25 \: m/s}}}}

∴ The option (b)25 m/s is the correct answer.

\begin{gathered}\end{gathered}

Lᴇᴀʀɴ Mᴏʀᴇ :

\star Velocity

{\longrightarrow{\small{\underline{\boxed{\bf{v = u  +  at}}}}}}

\star Displacement with positive accelerations

{\longrightarrow{\small{\underline{\boxed{\bf{s= ut  +  \dfrac{1}{2}{at}^{2}}}}}}}

\star Displacement with negative acceleration

{\longrightarrow{\small{\underline{\boxed{\bf{s= ut - \dfrac{1}{2}{at}^{2}}}}}}}

\star Displacement knowing initial and final speeds

{\longrightarrow{\small{\underline{\boxed{\bf{s= \dfrac{1}{2}\big(u + v \big)t}}}}}}

\star Velocity squared

{\longrightarrow{\small{\underline{\boxed{\bf{{v}^{2} =  {u}^{2} + 2as}}}}}}

\underline{\color{gray}{\rule{220pt}{2.5pt}}}

Similar questions