Question

A body moving with an initial velocity of 5 ms-1 attains a velocity of 15 ms−1 in 3 s. Then the displacement is .please ans fastly​

Answer 1

Answer:

GIVEN =>

initial velocity, u = 5m/s

final velocity, v = 15m/s

time = 3 sec

According to the question, first we will find acceleration,

a=v-u/t

 =15-5 / 3

 =10/3m/sec^2

Therefore, acceleration= 10/3 m/sec^2

Using equations of motion,

s=ut+1/2at^2                                    [let s be the displacement]

 =5 * 3+1/2 * 10/3 * 3 * 3

 = 15+10/6*9

 = 15+90/6

 = 15+15

 = 30m

Therefore the displacement will be 30m

Explanation:

Answer 2

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initial velocity (u)= 5 m/s

final velocity (v)= 15m/s

acceleration (a)= v-u/t

acceleration in this case= 15-5/3

= 10/3

= 3.3m/s^2

using second equation of motion

s= ut+1/2×at^2

s= 5×3+1/2×3.3×3^2

s= 15+29.7/2

s= 59.7/2

s = 29.85 m

displacement= 29.85m

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