Question

A body moving with certain initial velocity and acceleration of 4ms-2, has a displacement of 50m in 10 second. The finial velocity attained by it is

Answer 1

Answer:

Final velocity is 25m/s

Explanation:

Given:-

Acceleration(a) =4m/s^2

Displacement(s) =50m

Time taken(t) =10s

Initial velocity(u) =?

Final velocity(v) =?

STEP 1:-

We know,

=> s=ut+1/2at^2(substituting values)

=>50=u*10+1/2*4*10*10

=>50=10u+200

=>50-200=10u

=>-150=10u

=>-15m/s=u

STEP 2:-

We know,

=>v=u+at

=>v=-15+4*10

=>v=-15+40

=>v=25m/s

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Answer 2

Given :

A body moving with certain initial velocity and acceleration of 4 m/s² , has a displacement of 50m in 10 seconds

To Find :

Final velocity

Solution :

$\bigstar\ \; \underbrace{\sf \pink{s=ut+\dfrac{1}{2}at^2}}\\\\\bigstar\ \; \underbrace{\sf \green{v=u+at}}\ \; \bigstar$

where ,

• s denotes displacement
• u denotes initial velocity
• t denotes time
• a denotes acceleration
• v denotes final velocity
• u denotes initial velocity

Given ,

• a = 4 m/s²
• s = 50 m
• t = 10 s

$\bigstar\ \; \sf s=ut+\dfrac{1}{2}at^2\\\\\to \sf 50=u(10)+\dfrac{1}{2}(4)(10)^2\\\\\to \sf 50=10u+200\\\\\to \sf 10u=-150\\\\\leadsto \sf u=-15\ m/s\ \; \bigstar$

$\bigstar\ \; \sf v=u+at\\\\\to \sf v=(-15)+(4)(10)\\\\\to \sf v=-15+40\\\\\leadsto \sf \red{v=25\ m/s}\ \; \bigstar$

Final velocity attained by the body is 25 m/s .