Question

A body moving with change in its position with time as x = (3t2 + 2t + 1 )m. what is the acceleration of the body at
t = 5 sec

Answer 1

Answer:

Given,

x=t  

2

−4t+6

So, the change in velocity is:

dt

dx

​

=2t−4

Since velocity is changing,

At t=0,x  

1

​

=6

At t=2,x  

2

​

=2

So the magnitude of the distance traveled is:

6−2=4m

At t=3,x  

3

​

=3

So distance traveled from t=2s to t=3s

x  

3

​

−x  

2

​

=3−2=1m

Thus the total distance is:

4+1=5m

Explanation: