Question

A body moving with initial velocity of 5 m/s is subjected to acceleration of 2.5 m/s.
find its displacement in the next 4 seconds ​

Answer 1

Given:

Initial velocity of body, u= 5 m/s

Acceleration of body, a=2.5 m/s²

Time taken by body, t= 4 s

To Find:

Displacement of body

Solution:

We know that,

• According to second equation of motion for constant acceleration,

$\orange{\boxed{\bf{s=ut+\dfrac{1}{2}at^{2}}}}$

where,

u is initial velocity

a is acceleration

s is displacement

t is time taken

$\rule{190}{1}$

Let the displacement of body be 's'

On applying second equation of motion on body, we get

$\longrightarrow\rm{s=ut+\dfrac{1}{2}at^{2}}$

$\longrightarrow\rm{s=5(4)+\dfrac{1}{2}(2.5)(4)^{2}}$

$\longrightarrow\rm{s=20+\dfrac{1}{2}(2.5)(16)}$

$\longrightarrow\rm{s=20+\dfrac{40}{2}}$

$\longrightarrow\rm{s=20+20}$

$\longrightarrow\rm\green{s=40\:m}$

Hence, displacement of given body is 40 m.