Physics, asked by Rishabhj2005, 9 months ago

A body moving with speed of 30km/hr towards east turns sharply towards north at 40 km/hr , the magnitude of change of velocity is

Answers

Answered by shahir1
0

Explanation:

A car is moving towards the north with a velocity 20m/sec. After some time it starts to go towards the south with a velocity 20 m/sec. What is the change in the velocity of the car?

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The change in velocit of the car is = 40 m/sec

Welcome to the Vector mechanics, Velocity is a vector quantity which depends both on magnitude and the direction.

In the above scenario, the magnitude remained the same but the direction changed by 180 degrees...

v1 = 20 m/sec

v2 = 20m/sec cos a(angle between the two vectors) = -20

dv = v2-v1

= (-20) - (20)

= -40 m/sec

The negative sign indicates that the car is moving in the opposite direction relative to the initial direction

  • BRO ITS NOT BODY IT IS CAR

HOPE THIS HELPS YOU

MARK AS BRILLIANT

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