Question

A body moving with uniform acceleration 2m/s2 covers a distance of 150 m in 10 seconds. Then, the initial velocity of the body is

Answer 1

Answer:

answer is 15

Explanation:

150/10=15

Answer 2

Solution :-

As per the given data ,

• Acceleration = 2 m/s²
• Distance covered = 150 m
• Time taken = 10 s

As the body is moving with uniform acceleration let us use the second kinematic equation in order to find the initial velocity of the body

Hence ,

⇒ s = ut + at ² / 2

here ,

• s = distance traveled
• u = initial velocity
• t = time taken
• a = acceleration

⇒ 150 = u x 10 + 2 x 100 / 2

⇒ 150 = 10 u + 100

⇒ 10 u = 50

⇒ u = 5 m/s

The initial velocity of the body is 5 m/s

Other Formulas

Second equation of motion ,

⇒ s = ut + at² / 2

Third equation of motion ,

⇒ v² = u ² + 2as

Distance covered by the body in n th second ,

⇒Sn = u + a(2n -1 ) / 2