Question

A body moving with uniform acceleration along a straight line has a speed of 5 metre per second when passing a point p and 15 metre per second when passing a point q in its path calculate its speed at the midpoint of PQ

Answer 1

Explanation:

Let the midpoint of AB be M and A and B are S m apart. Also, let acceleration of the body is A m/s²

Let velocity of body-

At A be U = 20 m/s

At B be V = 30 m/s

At C be W

For uniform acceleration motion, we know that

v² = u² + 2as

Now, here u = U, a = A, s = S, v = V.

Therefore, V² = U² + 2AS => S = (V² - U²)/2A—(1)

Now, for point M, s = S/2, u = U, v = W.

Therefore, W² = U² + 2A(S/2) => W² = U² + AS

Putting value of S in above equation from equation (1)—

W² = U² + A(V² - U²)/2A = U² + (V² - U²)/2

=> W² = (U² + V²)/2 => W =√ (U²+V²)/2

Now, put the values

W² = (20²+30²)/2 = (400+900)/2 = 1300/2 =650

W = √650

Approx 25.5 m/s

Answer 2

Answer:

Here is the correct answer

MARK AS BRAINLIEST