Question

A body moving with uniform acceleration describes 12 metre in the third second of its motion and 20 metre in the fifth second. Find the velocity after 10 sec .
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Answer 1

Answer:

42 m/s.

Explanation:

we have a formula to find this ,that is,

Sn=U+a(n-- 1/2)...

so, 12=u+a(3-1/2).

12=u+a(5/2),

12=u+(5a/2),

24=2u+5a.

and, 20=u+a(5-1/2),

20=u+(9a/2),

40 =2u+9a....

by adding both equations ,we get

16=4a ,,, a=4m/s^2

then substitue a in the equation

40=2u+9*4,,

2u=4,

u=2m/s....

v=u+at

v=2+4*10

v=2+40,,

v=42m/s.....

thats it ..............

Answer 2

good luck this is the correct answer

Mark as brainly