Question

A body moving with uniform acceleration describes 40m in the first 5sec and 65m in the next 5sec. it's initial velocity is

Answer 1

We know that

S =ut+1/2 at(square)

Firstly

40=u5+1/2a×25

8=u+5/2a

By multiply 2 both side

16=2u+5a.........eq(1)

Now 2nd portion

40+65=105m total distance covered in 10 sec

105=10u+1/2a×100

Divide by 5 on both side

21=2u+10a.........eq(2)

Now

16=2u+5a ×2......eq(1)

21=2u+10a ×1.......eq(2)

On substraction eq(1)-eq(2)

We get

11=2u

U=11/2

U=5.5 m/s

I hope u people understand

Answer 2

Answer:

shaha Alam Khan like kiya hai pls bharosa hai na tere

Explanation:

ha to be a good morning dear ydyu to be a good time to come over and over again top-up in your account can and should arrive in time to explore new