Question

A body moving with uniform acceleration has a velocity of of minus 11th centimetre per second when its X co-ordinate is 3 CM if its X co-ordinate to second letter is minus 5 second what is the magnitude in centimetre per second square of its acceleration​

Answer 1

Answer:

acceleration = 48 m/s²

Explanation:

X co-ordinate is 3 CM  then Velocity =  - 11 cm/s

X co-ordinate is 2 CM  then Velocity =  - 5 cm/s

Distance = 2 - 3 = - 1

Using V² - U² = 2aS

(-5)² - (-11)² = 2a(-1)

=> 25 - 121 = -2a

=> -96 = -2a

=> a = 48

acceleration = 48 m/s²