Question

A body moving with uniform acceleration is havia
velocity 2 m/s and 8 m/s at t = 1 s and t = 45
respectively. Then average velocity of particle in the
time interval t = 1 s to t= 4 s is
(1) 2 m/s
(2) 3 m/s
(3) 5/3 m/s
(4) 5 m/s​

Answer 1

5m/s

Explanation:

Vavg=v1+v2/2

2+8/2=10/2=5m/s