Question

A body moving with uniform acceleration is having velocity 2m/s and 8m/s at t=1and t=4s .the average velocity of the particle in time interval t=1to t=4sec
​

Answer 1

Dear Rohit,

● Answer -

vavg = 5 m/s

◆ Explaination -

# Given -

t1 = 1 s

t2 = 4 s

v1 = 2 m/s

v2 = 8 m/s

a = ?

# Solution -

Time taken for motion is -

t = t2 - t1

t = 4 - 1

t = 3 s

Uniform acceleration is calculated by -

v2 = v1 + at

8 = 2 + a × 3

a = (8 - 2) / 3

a = 2 m/s^2

Distance tarvelled hy body is given by

s = v1t + 1/2 at^2

s = 2 × 3 + 1/2 × 2 × 3^2

s = 15 m

Average velocity is calculated by -

vavg = s / t

vavg = 15 / 3

vavg = 5 m/s

Hence, average velocity is 5 m/s.

* Alternatively, you can simply use vavg = (v1 + v2) /2

Hope I was useful.

Answer 2

Answer:

5 m/s

Explanation:

see the image attached